6x-[x+(3x+1)-8]=5

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Solution for 6x-[x+(3x+1)-8]=5 equation:


Simplifying
6x + -1[x + (3x + 1) + -8] = 5

Reorder the terms:
6x + -1[x + (1 + 3x) + -8] = 5

Remove parenthesis around (1 + 3x)
6x + -1[x + 1 + 3x + -8] = 5

Reorder the terms:
6x + -1[1 + -8 + x + 3x] = 5

Combine like terms: 1 + -8 = -7
6x + -1[-7 + x + 3x] = 5

Combine like terms: x + 3x = 4x
6x + -1[-7 + 4x] = 5
6x + [-7 * -1 + 4x * -1] = 5
6x + [7 + -4x] = 5

Reorder the terms:
7 + 6x + -4x = 5

Combine like terms: 6x + -4x = 2x
7 + 2x = 5

Solving
7 + 2x = 5

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + -7 + 2x = 5 + -7

Combine like terms: 7 + -7 = 0
0 + 2x = 5 + -7
2x = 5 + -7

Combine like terms: 5 + -7 = -2
2x = -2

Divide each side by '2'.
x = -1

Simplifying
x = -1

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